6 СЕМЕСТР / ЛР / ЛР7 / БД ЛР7

employees ee)

group by l.city order by AVG_SALARY) union all

(select 'Workers' EMP

,l.city

,count(distinct e.employee_id) CNT_WORKER

,round(avg(e.salary)) AVG_SALARY

from employees e

join locations l using(location_id)

where e.employee_id not in

(select distinct d.manager_id id from departments d

where d.manager_id is not null

union

select distinct e.manager_id id from employees e where

print('\n\nРезультат вызова функции select_data:\n', result_proc)

# создаине функции select_data1 cursor.execute("""

CREATE OR REPLACE FUNCTION select_data1(id_dept int) RETURNS SETOF departments AS $$

SELECT * FROM departments WHERE departments.department_id >

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id_dept;

$$ LANGUAGE SQL;

""") # выполнение запроса connection.commit() #внесение изменений в БД

print('\n\nРезультат вызова функции select_data1:\n', result_proc)

# моя функция cursor.execute("""

CREATE OR REPLACE FUNCTION my_func(min_salaryy int) RETURNS table (department_name character

,WORKER_COUNT integer

,AVG_SALARY integer) AS $$

select d.department_name

,count(*) WORKER_COUNT

,round(avg(e.salary)) AVG_SALARY from departments d

join employees e using(department_id) where

e.salary > min_salaryy group by d.department_name; $$ LANGUAGE SQL;

""") # выполнение запроса connection.commit() #внесение изменений в БД

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результатом

print('\n\nРезультат вызова функции my_func:\n', result_proc)

connection.close() # закрытие соединения cursor.close() # закрытие cursor

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